Calculate the freezing point of a water solution at each concentration.

1.40m?

What are the steps to calculate this?

delta T = i*Kf*m and I assume all of the solutions you have are non-electrolytes and i = 1.

You know Kf (the freezing point constant) and if you don't it will be in your text and it's all over the web. m is the molality and that's in the problem (in this case 1.40). Calculate delta T and subtract that from the normal freezing point of water which is 0 C..

So would it be

Delta T = i*Kf(0 degrees C)*1.40
Delta T/Kf *1.40v= i?

No. In trying to avoid confusing you because I didn't know what other compounds you had (and some may have been ionic), I ended up confusing you by including the i. Just forget the i or if yu want to keep it there, note that I TOLD you it was 1 for this problem.

delta T = Kf*m
Did you look up Kf? Evidently not. Kf is the freezing point constant for H2O and has a value of 1.86, i = 1. m = 1.40 from the problem.
delta T = 1*1.86*1.40.
Find delta T and subtract from zero to find the new freezing point.

To calculate the freezing point of a water solution at a specific concentration, you can use the formula known as the Freezing Point Depression equation. This equation relates the change in freezing point to the concentration of the solute.

The steps to calculate the freezing point of a 1.40 m (molality) water solution are as follows:

1. Determine the molality of the solution: In this case, the given concentration is 1.40 m, which means that there is 1.40 mole of solute per kilogram of solvent (water).

2. Identify the molal freezing point constant (Kf) for water: This constant represents the change in freezing point per molal concentration of solute. For water, the Kf value is approximately 1.86 °C/molal.

3. Calculate the change in freezing point (∆Tf): Use the formula ∆Tf = Kf * molality. In this case, it would be ∆Tf = 1.86 °C/molal * 1.40 m.

4. Subtract the change in freezing point (∆Tf) from the normal freezing point of water (0 °C): Since the freezing point of pure water is 0 °C, subtract ∆Tf from it. Therefore, the freezing point of the solution would be 0 °C - (∆Tf).

5. Calculate the freezing point of the water solution: Now that you have the value of (∆Tf), subtract it from 0 °C to find the freezing point of the solution.

By following these steps, you can calculate the freezing point of a water solution at a concentration of 1.40 m.