A bag contains 5 red marbles, 4 blue marbles, and 1 green marble. If a marble is selected at random, what is the probability that it is not blue?
Because there are a total of 10 marbles in the bag, and 4 of them are blue, the probability that it is not blue is:
(10-4)/10, 4 of them are blue so subtract 4 from the total of 10, and place that over 10, the total.
6/10, or 3/5.
Perfect that is what I got
A box contains 3 blue, 5 red, 4 white marbles. If one marble drawn at random: find probability of blue given not white. Find probability of not red given not white.
Well, let's see. The total number of marbles in the bag is 5 (red) + 4 (blue) + 1 (green), which equals 10 marbles.
To find the probability of not selecting a blue marble, we need to consider the number of non-blue marbles, which is 5 (red) + 1 (green) = 6 marbles.
Therefore, the probability of selecting a non-blue marble is 6/10, which simplifies to 3/5.
So, the probability of not selecting a blue marble is 3/5, or approximately 60%.
Now you can safely bet that the clown in the bag isn't feeling blue!
To find the probability that a marble is not blue, we need to consider the total number of marbles and the number of marbles that are not blue.
The bag contains a total of 5 red marbles, 4 blue marbles, and 1 green marble, making a total of 10 marbles.
To find the number of marbles that are not blue, we subtract the number of blue marbles from the total number of marbles: 10 - 4 = 6.
Therefore, there are 6 marbles that are not blue.
The probability of selecting a marble that is not blue can now be determined by dividing the number of marbles that are not blue by the total number of marbles:
Probability = Number of marbles that are not blue / Total number of marbles
Probability = 6 / 10
Simplifying, we find that the probability of selecting a marble that is not blue is 3/5 or 0.6, which can also be expressed as 60%.