In the sun, nuclear fusion takes place. If the decrease in mass isa 0.006 50g, how much energy is released?
dE = dm*c^2
E = (0.00650/1000)*3E8^2 =?
The 1000 converts g to kg.
To calculate the amount of energy released during nuclear fusion, we can use Albert Einstein's mass-energy equivalence equation, E = mc^2, where E is the energy released, m is the decrease in mass, and c is the speed of light (which is approximately 3 x 10^8 m/s).
Given that the decrease in mass is 0.00650 g, we need to convert it to kilograms before using it in the equation. There are 1000 grams in a kilogram, so the decrease in mass is 0.00650 g * (1 kg / 1000 g) = 0.00000650 kg.
Now, we can calculate the energy released:
E = (0.00000650 kg) * (3 x 10^8 m/s)^2
First, we calculate the value inside the parentheses:
(3 x 10^8 m/s)^2 = 9 x 10^16 m^2/s^2
Now, we multiply this value by the decrease in mass:
E = (0.00000650 kg) * (9 x 10^16 m^2/s^2) = 5.85 x 10^12 J
Therefore, the energy released during nuclear fusion is approximately 5.85 x 10^12 Joules.
To calculate the amount of energy released in the sun during nuclear fusion, we can use Einstein's famous equation, E = mc². In this equation, E represents the energy, m represents the change in mass, and c represents the speed of light (approximately 3 x 10^8 m/s).
Given that the decrease in mass is 0.00650 g, we need to convert it to kilograms (kg) since the speed of light is measured in meters per second (m/s).
To convert grams to kilograms, we divide by 1000, so the change in mass becomes 0.00650 g ÷ 1000 = 0.0000065 kg.
Now we can use the formula:
E = (change in mass) x (speed of light) squared
E = 0.0000065 kg x (3 x 10^8 m/s)²
E = 0.0000065 kg x (9 x 10^16 m²/s²)
Calculating this expression, we find:
E ≈ 5.85 x 10^11 joules
Therefore, approximately 5.85 x 10^11 joules of energy are released during nuclear fusion in the sun.