how high is a tree that cast a 48ft shadow at the time a 12 ft pole cast a shadow which is 12 ft long.
the tree hight is?
To find the height of the tree, we can use a proportion.
Let's assign variables:
Let h be the height of the tree in feet.
Let x be the length of the shadow cast by the tree in feet.
From the information given, we know that when a 12 ft pole casts a 12 ft shadow, the tree casts a 48 ft shadow.
We can set up the following proportion:
12 ft (length of the pole's shadow) : 12 ft (length of the pole) :: 48 ft (length of the tree's shadow) : h (height of the tree)
This can be written as:
12 ft / 12 ft = 48 ft / h
To solve for h, we can cross-multiply and then divide:
12 ft * h = 12 ft * 48 ft
h = (12 ft * 48 ft) / 12 ft
Simplifying,
h = 576 ft / 12 ft
h = 48 ft
Therefore, the height of the tree is 48 feet.