how high is a tree that cast a 48ft shadow at the time a 12 ft pole cast a shadow which is 12 ft long.

the tree hight is?

To find the height of the tree, we can use a proportion.

Let's assign variables:

Let h be the height of the tree in feet.
Let x be the length of the shadow cast by the tree in feet.

From the information given, we know that when a 12 ft pole casts a 12 ft shadow, the tree casts a 48 ft shadow.

We can set up the following proportion:

12 ft (length of the pole's shadow) : 12 ft (length of the pole) :: 48 ft (length of the tree's shadow) : h (height of the tree)

This can be written as:

12 ft / 12 ft = 48 ft / h

To solve for h, we can cross-multiply and then divide:

12 ft * h = 12 ft * 48 ft

h = (12 ft * 48 ft) / 12 ft

Simplifying,

h = 576 ft / 12 ft

h = 48 ft

Therefore, the height of the tree is 48 feet.

Gee -- it must be 48 feet.