could someone please explain how to work out the highest fhydride and the highest flouride of ununhexium ,if the valance is 6 UUHF6 AND UUH6 ,I THOUGHT IT WOULD HAVE BEEN UUH2COULD SOMEONE EXPLAIN MANY THANKS

Question

could someone please explain how to work out the highest fhydride and the highest flouride of ununhexium ,if the valance is 6 UUHF6 AND UUH6 ,I THOUGHT IT WOULD HAVE BEEN UUH2COULD SOMEONE EXPLAIN MANY THANKS

hi Jill
i sent you a message are you able to help on q4 and q3 by any chance

hi mickey what number as there is many parts to questins 1-3

thanks jill
im stuck on part d mainly

is it question 1d or 3d

d but if you can help with part a it would be appreciate it

q3 part a and partd of the same question

7 alpha emissions would mean isatope of 264 atomic number=102 final product being woul put it in a lanthanide

how is this worked out as you have to show your workings

₁₁₆Uuh²⁹²==>7 ₂He⁴ + ₁₀₂X²⁶⁴

Now go to http://www.webelements.com/
and find the element X with an atomic number of 102.

I posted the Uuh losing 7 alpha particles just below; however, if you will repost you entire question again where we can see it we may be able to help with the other parts.

so that means x = the element No

That is right.

thank you so much

Answer 1

To work out the highest fluoride and hydride of ununhexium (Uuh) with a valence of 6, you need to consider the valence and the chemical properties of the element.

For Uuh with a valence of 6, the highest fluoride would be UuhF6. This means that ununhexium forms a compound with six fluoride ions, resulting in a formula of UuhF6.

However, for the highest hydride, it would not be UuhH6 as you thought. The valence of 6 means that ununhexium can form compounds with six hydrogen ions. So the highest hydride of ununhexium would actually be UuhH6.

To explain why it's UuhH6 instead of UuhH2, we need to consider how many hydrogen ions can be bonded to ununhexium based on its valence. The valence of 6 suggests that there are six available bonding sites for hydrogen. Therefore, the formula would be UuhH6, indicating that ununhexium can form a compound with six hydrogen ions.

It's important to note that the valence of an element determines how many electrons it can gain, lose, or share in a chemical reaction. The valence dictates the formation of compounds and helps determine the chemical properties of an element.

I hope this explanation helps clarify how to work out the highest fluoride and hydride of ununhexium based on its valence.