Ms. Meyers said the theatre usually charge $9 per student. On student night, the tickets are $6 per student and she can bring 47 more students for the same cost. How many students can Ms. Meyer bring to the theatre?
10
Let's assume the usual number of students that Ms. Meyers can bring is 'x'.
According to the given information, the price per ticket on student night is $6 instead of the usual $9. This means that for the same cost, Ms. Meyers can bring 47 more students.
So, the cost of the usual number of students (x students) is $9 per student, and the cost of the increased number of students (x + 47 students) is $6 per student.
To find the number of students Ms. Meyers can bring, we'll set up an equation:
9x = 6(x + 47)
Distributing on the right side of the equation:
9x = 6x + 282
Combining like terms:
9x - 6x = 282
3x = 282
Dividing both sides by 3:
x = 282 / 3
Simplifying:
x = 94
Therefore, Ms. Meyers can bring 94 students to the theater.
To solve this problem, we can set up an equation based on the information given.
Let's assume that the number of students Ms. Meyers can bring to the theater is x.
According to the given information, the theater usually charges $9 per student. So the cost of the tickets for x students is 9x dollars.
On student night, the tickets are $6 per student. So the cost of the tickets for x + 47 students is 6(x + 47) dollars.
Since the cost for both scenarios is the same, we can set up an equation:
9x = 6(x + 47)
Now, let's solve this equation to find the value of x, which represents the number of students Ms. Meyers can bring to the theater.
Expanding the equation:
9x = 6x + 282
Combining like terms:
9x - 6x = 282
3x = 282
Divide both sides of the equation by 3:
x = 282 / 3
x = 94
Therefore, Ms. Meyers can bring 94 students to the theater.