Chemistry Physics

How many Btu of heat are required to melt 33.0 lb of ice at 32°F and to raise the temperature
of the melted ice to 72°F?

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  1. q1 = heat to change phase ice from solid at 32 F to liquid at 32F.
    q1 = mass ice x heat fusion

    q2 = heat to raise T from 32 F to 72 F
    q2 = mass H2O x specific heat x (Tfinal-Tinitial)

    Then total btu = q1 + q2

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  2. So,is this the setup to find heat?
    q1= 33.0 X 3.35X10^5
    q2=2.26X10^6*1*(72-42)

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  3. on q2 I mean (72-32)

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  4. I don't think so. What's 3.35E5? Usually I don't work in BTU/lb but that isn't the number I see for heat fusion in the tables.

    Then for q2 what is 2.26E6?

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  5. I got it all wrong, confusing the tables

    But for Q1
    Q1=0.51*33.0*80cal/kg (not sure how to
    convert to BTU)

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  6. You can use Google to convert but you want q in btu so why not look up heat fusion in btu/lb for metling and specific heat in btu/lb*F for raising the T from 32 to 72.
    I looked up the heat fusion and came away with 144 btu/lb but you should confirm that. I also looked up the specific heat H2O and it appears it is more less constant at about 1.0 btu/lb*F. Again, you should confirm that.

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  7. thanks
    144 BTU/lb is the heat fusion of water and ice

    and the specific heat for ice is 0.51BTU/lb

    So would I need to set it up Q1 like this?
    0.51*33.0*144

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  8. No. Look back at my original response.
    q1 for changing phase of ice from solid at 32 F to liquid at 32 F is
    q1 = mass ice x heat fusion.
    q1 = 33 lb x 144 btu/lb = ? btu

    You don't need specific heat ice, only the heat fusion at the melting point.

    I looked up specific heat water and found about 1 btu/lb*F (but you should confirm that), then (from my first response)
    q2 = mass water x specific heat H2O x (Tfinal-Tinitial)
    q2 = 33 x 2.0 x (72-32) = ? btu. That's the amount of heat that must be added to liquid water at 32F to raise the temperature from 32F to 72F.
    Then qtotal btu = q1 + q2

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  9. =6072btu
    thank you for clearing this up, really appreciate all the help.

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  10. q2 = mass water x specific heat H2O x (Tfinal-Tinitial)
    q2 = 33 x 2.0 x (72-32) = ? btu. That's the amount of heat that must be added to liquid water at 32F to raise the temperature from 32F to 72F.
    Then qtotal btu = q1 + q2

    That should be a 1.0 and not a 2.0 above. I hope you confirmed that and used the right number.

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  11. yes I noticed it, but its still the right setup. thanks

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