math

A three- digit number is eleven times the two-digit formed by using the hundreds and the units digit of the three - digit number respectively, in the tens and units place of the two - digit number. If the difference between the digit in tens place and the digit in hundreds place is 1 then what is the digit in units place?

How can I frame the solution?? Can you explain me

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  1. If the digits are a,b,c then the value of the original 3-digit number is

    100a+10b+c

    So, now we know that

    100a+10b+c = 11(10a+c)
    b-a = 1
    we want to find c

    100a + 10(a+1) + c = 110a+11c
    100a+10a+10+c = 110a+11c
    10+c = 11c
    c = 1

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  2. Thank you.

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