Miriam is four years older than Ricardo. Ten years ago Miriam was 3 times as old as Ricardo was then. How old are they now?
Ricardo --- x years
Miriana ---- x+4
Ten years ago:
Ricardo --- x-10
Miriam --- x+4 - 10 = x-6
x-6 = 3(x-10)
easy to solve ...
let me know what you get
Ricardo is 3 years older than Courtney. In 5 years the sum of their ages will be 81. How old is Ricardo now?
To solve this problem, we can set up two equations based on the information given.
Let's assume Ricardo's current age is "R" and Miriam's current age is "M."
According to the first sentence, Miriam is four years older than Ricardo, so we can write the equation: M = R + 4.
According to the second sentence, ten years ago Miriam was three times as old as Ricardo was then. So, ten years ago, Miriam's age was (M - 10) and Ricardo's age was (R - 10). We can write the second equation as: M - 10 = 3(R - 10).
Now, we have a system of two equations that we can solve to find the values of R and M.
Substituting the value of M from the first equation into the second equation, we get:
(R + 4) - 10 = 3(R - 10)
R - 6 = 3R - 30
2R = 24
R = 12
Using this value of R, we can substitute it back into the first equation to find M:
M = R + 4
M = 12 + 4
M = 16
Therefore, Ricardo is currently 12 years old, and Miriam is currently 16 years old.