Yes, it is I again, with yet another math problem. The question is; In a bag, there are 8 white marbles, 8 blue marbles, 7 red marbles, and 6 yellow marbles. How many marbles does it take to pull out 3 marbles of the same color.
(A)6
(B)9
(C)12
(D)15
(E)I forgot the last one
I am totally confused on this question.
b is the answer
Think about it two white, two blue, two red, and two yellow makes eight. than the night has the third one.
does any one know every answer to this practice
No problem! Let's break down the question and figure out the solution together.
In the bag, we have a total of 8 white marbles, 8 blue marbles, 7 red marbles, and 6 yellow marbles. We want to know how many marbles we need to pull out in order to guarantee that we have picked 3 marbles of the same color.
To find the minimum number of marbles required, we need to consider the worst-case scenario. In this case, the worst-case scenario is pulling out 2 marbles of each color (since any additional marble will guarantee 3 of the same color).
So, let's calculate the number of marbles needed for the worst-case scenario:
2 white marbles + 2 blue marbles + 2 red marbles + 2 yellow marbles = 8 marbles
However, this answer only applies to the worst-case scenario. To guarantee that we have pulled out 3 marbles of the same color, we need to consider the best-case scenario as well. In the best-case scenario, we would randomly pick 3 marbles of the same color on our first attempt.
Therefore, the minimum number of marbles required would be 3. We can conclude that the correct answer is (A) 6 marbles, as it covers both the worst-case and best-case scenarios.
I hope this explanation helps!