A solution contains 100 mg/mL of a drug and the recommended dose is 50 mg/Lb once a day. How much solution would be needed for one dose to be administered to a 20 kg patient?
Not sure if this is correct, but this is how I'd do this problem.
20kg x (1 lb)/(2.20kg )= 9.09 lbs
9.09 lbs x (50mg) / (1 lb)= 454.5 mg
454.5 mg x(1ml)/(100mg)= 4.545ml
To find out how much solution is needed for one dose to be administered to a 20 kg patient, we first need to determine the patient's weight in pounds.
To convert kilograms to pounds, we'll use the conversion factor: 1 kg = 2.20462 lbs.
Weight of the patient in pounds:
20 kg × 2.20462 lbs/kg = 44.0924 lbs (rounding to 44 lbs)
Now we can calculate the recommended dose for the patient, which is 50 mg per pound of body weight.
Dose for the patient:
50 mg/Lb × 44 lbs = 2200 mg
The solution concentration is given as 100 mg/mL, which means that for every 1 mL of solution, there are 100 mg of the drug.
To find the volume of the solution needed for the dose, we need to divide the dose (in mg) by the concentration (in mg/mL).
Volume of solution needed:
2200 mg ÷ 100 mg/mL = 22 mL
Therefore, for one dose to be administered to a 20 kg patient, 22 mL of the solution would be needed.