A child pulls a 13 kg sled across the snow at a constant 1.6 m/s [N] applying a force of 51 N [N 25 deg U]. How much work have they done after pulling for 44 m? Round answers to the nearest whole number.
m=13kg
Vcon=1.6m/s
F=51N
d=44
cos theta=25
W=Fdcostheta?
I don't know how to this because I did a similar question, plugged everything in and got it wrong.
yes, that is it
k thanks :)
i realized the last time when i got it wrong, I put in;
w=Fdcos20
=51(44)(20)
when i should've put;
w=51(44)(cos20)
To calculate the work done by the child in pulling the sled, you can use the equation:
Work (W) = Force (F) × Distance (d) × cos θ
where:
- W represents work,
- F represents force,
- d represents distance, and
- θ represents the angle between the direction of force and the direction of motion.
Given:
- Mass (m) of sled = 13 kg
- Constant velocity (Vcon) = 1.6 m/s [N]
- Force (F) applied by the child = 51 N [N 25 deg U]
- Distance (d) pulled = 44 m
To use the equation, we need to resolve the force into its horizontal component. Since the sled is pulled at an angle of 25 degrees, the horizontal component of the force can be calculated as:
F horizontal = F × cos θ
F horizontal = 51 N × cos 25 degrees
Using a calculator, we find that the horizontal component of the force is approximately 45.9 N.
Now, we can calculate the work done. Plugging in the values into the equation:
W = F horizontal × d
W = 45.9 N × 44 m
Using a calculator, we find that the work done is approximately 2020.8 Joules.
Rounding the answer to the nearest whole number, the work done by the child after pulling for 44 m is 2021 Joules.