a ship covered a distance of 41 km due north and then 23 km due east and again 15 km towards north direction.how far is it from the point where it started?
so in effect the ship went 41 + 15 or 56 north
and 23 east.
so
d^2 = 56^2 + 23^2 = 3665
d =√3665 = 60.5 km
To find the distance between the final point and the starting point, you can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, we have a right triangle with two sides along the north direction (41 km and 15 km) and one side along the east direction (23 km). Let's call the distance between the starting point and the final point "d".
To calculate "d", we can apply the Pythagorean theorem as follows:
d^2 = (41 km + 15 km)^2 + (23 km)^2
d^2 = 56 km^2 + 529 km^2
d^2 = 625 km^2
Taking the square root of both sides:
d = √625 km
d = 25 km
Therefore, the ship is 25 km away from the point where it started.