# Intermediate Algebra

A bank loaned out 15,000part of it at a rate of 6% per year and the rest at 14%per year. If the interest received in one year totaled 1500, how much was loaned at 6%?

0.6x +14(15,000-x)=1500
0.6+2100-14=1500
1x=1500-2100
x=600
x=600/1
x=600 loaned @6%
15,000-600=14,400 loaned @14%

Is this correct

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1. sloppy use of the decimal place
and your solution makes absolutely no sense.

if x is the amount loaned at 6% ...

.06x + .14(15000-x) = 1500
.06x + 2100 - .14x = 1500
-.08x = -600
x = 600/.08 = 7500

So \$ 7500 was loaned at 6% and \$7500 at 14%

check:
.06(7500) + .14(7500) = 1500

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posted by Reiny
2. inccorect

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2. 👎 0

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