The block of mass 1.43443 kg has an acceleration of 3.6 m/s^2 as shown.
What is the magnitude of F? Assume the
acceleration due to gravity is 9.8 m/s^2
and the surface is frictionles
F = m*a
To find the magnitude of force (F), we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
Given:
Mass (m) = 1.43443 kg
Acceleration (a) = 3.6 m/s^2
Acceleration due to gravity (g) = 9.8 m/s^2
Using the formula: F = m * a
F = 1.43443 kg * 3.6 m/s^2
F = 5.165548 N
Therefore, the magnitude of force (F) acting on the block is approximately 5.165548 N.
To find the magnitude of force (F), we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. Mathematically, this can be represented as:
F = m * a
In this case, the mass (m) of the block is given as 1.43443 kg, and the acceleration (a) is given as 3.6 m/s^2. Substituting these values into the equation, we can calculate the magnitude of force (F).
F = (1.43443 kg) * (3.6 m/s^2)
F ≈ 5.16475 N
Therefore, the magnitude of force (F) is approximately 5.16475 Newtons.
Please note that in this problem, we assumed a frictionless surface and neglected the force of gravity, as it was not mentioned in the question.