If you put hydrogen peroxide on a cut, you’ll notice that it bubbles. The bubbles are diatomic oxygen which is effectively “sterilizing” the wound. If you had 10 g of H2O2, how many grams of oxygen would you form on the cut.
To determine how many grams of oxygen would be formed by 10 grams of hydrogen peroxide (H2O2), we need to first understand the stoichiometry of the reaction.
The balanced equation for the decomposition of hydrogen peroxide is:
2 H2O2 -> 2 H2O + O2
From the equation, we can see that for every 2 moles of hydrogen peroxide, we obtain 1 mole of oxygen gas. To find the molar mass of oxygen (O2), we can refer to the periodic table, which gives us a value of approximately 32 g/mol.
Now, we can proceed with the calculations:
1 mole of oxygen (O2) = 32 grams
2 moles of hydrogen peroxide (H2O2) = 2 * molar mass of H2O2
= 2 * (1 g/mol + 1 g/mol)
= 4 grams
Now, we can set up a proportion to calculate the mass of oxygen:
(1 mole of O2 / 2 moles of H2O2) = (32 grams of O2 / X grams of H2O2)
Simplifying the proportion:
1 / 2 = 32 / X
Cross-multiplying:
X = 2 * 32 / 1
X = 64 grams
Therefore, if you had 10 grams of hydrogen peroxide, it would yield approximately 64 grams of oxygen gas when it decomposes.