How many liters of CO2 gas are contained in a 3.16 liters of a gas mixture which is 8.1% (v/v) CO2?
They never gave us the formula or a process to figure this out in class. Will you please help?
The usual formula for %v/v is (volume gas/total volume)*100 = %.
(x L CO2/3.16L)*100 = 8.1%
Solve for x L CO2.
Would the answer be .25596?
8.1/100= .081
.081*3.16= .25596
Yes but if your prof is picky about the number of significant figures you will get marked down. You're allowed 2 places (because of the 8.1 so you should round that number fo 0.26 AND place a unit on it of L.
Of course! I'd be happy to help you figure out how to solve this problem.
To find out how many liters of CO2 gas are contained in a 3.16 liters gas mixture, we need to use the given information that the gas mixture is 8.1% (v/v) CO2.
Here's the step-by-step process to solve this problem:
Step 1: Convert the percentage to a decimal fraction.
8.1% is equivalent to 8.1/100, which is 0.081.
Step 2: Multiply the decimal fraction by the volume of the gas mixture.
0.081 x 3.16 = 0.256 liters.
Therefore, there are approximately 0.256 liters of CO2 gas contained in 3.16 liters of the gas mixture.
I hope this explanation helps you understand how to solve this type of problem in the future! If you have any further questions, feel free to ask.