A traveler leaves Lima, Peru ( approximately 12 degrees S. Lat. And 90 degrees W. long.) at 8:00 am on Tues. Oct. 3rd and travels for 14 hrs before arriving in Sydney, Australia ( approx. 34 degrees S and 150 degree E). what time and what day would the traveler arrive according to Sydney time? ( show work pleas)
Thank you for using the Jiskha Homework Help Forum. Again, I used the World Clock:
http://www.timeanddate.com/worldclock/
If it is 8:00 a.m. on Tues. Oct 3 and you travel 14 hours, it should then be 16 hours later plus the 14 hours you travel. So if it's 10 p.m. on Wed when you arrive in Sydney, the local time should be Thursday, 2 p.m.
To determine the arrival time of the traveler in Sydney, we need to take into account the time difference between Lima and Sydney.
1. First, find the time difference between Lima and Sydney. Lima is located at approximately 90 degrees west longitude, while Sydney is located at approximately 150 degrees east longitude. Each degree of longitude corresponds to approximately 4 minutes of time difference. So, the time difference between Lima and Sydney is:
(150 - (-90)) * 4 = 240 * 4 = 960 minutes
2. Convert the time difference to hours by dividing by 60:
960 minutes / 60 = 16 hours
So, the time difference between Lima and Sydney is 16 hours.
3. Add the travel time of 14 hours to the departure time of 8:00 am on Tuesday, October 3rd:
8:00 am + 14 hours = 22:00 (10:00 pm)
4. Account for the time difference by adding 16 hours to the departure time:
10:00 pm + 16 hours = 2:00 pm (next day)
So, according to Sydney time, the traveler would arrive at 2:00 pm on the next day (Thursday).
Therefore, the traveler would arrive in Sydney at 2:00 pm on Thursday according to Sydney time.