0.05 L of chlorine gas is bubbled through 0.5 L of 2 M sodium Bromide solution.

-What type of reaction is this ?
A) Single Replacment B) Double Replacement
C) Synthesis D) Decomposition E) Combustion
- What product(s) will be predicted for this reaction? (bubble all that apply)
A) No Products Form B) Na C) Br D) NaCl
E) Br2

Cl will replace Br, so Br2 bubbles can form, but much is likely to go into solution. Reaction is single replacement.

Thank you so much for explaining this to me !!! I honestly don't understand my chemistry teacher sometimes!!!

Cl2(g) + 2NaBr(aq) ==> Br2(l) + 2NaCl

The second part of the question. You "bubble in" (I guess it means mark in) E which is Br2 and D which is NaCl.

To determine the type of reaction and predict the products for the given reaction, we need to understand the reactions that can occur between chlorine gas (Cl₂) and sodium bromide (NaBr) solution.

The reaction between chlorine gas and sodium bromide solution can be categorized as a type of reaction called a Single Replacement Reaction or Displacement Reaction. In this type of reaction, an element replaces or displaces another element in a compound.

The general equation for this type of reaction is:
A + BC → AC + B

In our case, chlorine gas (Cl₂) will be the element trying to replace bromine (Br) in sodium bromide (NaBr) solution. So, we can write the reaction equation as follows:
Cl₂ + 2NaBr → 2NaCl + Br₂

Now, let's analyze the reactants and products to predict the outcomes of the reaction.

Reactants:
- Chlorine gas (Cl₂)
- Sodium bromide solution (NaBr)

Products:
- Sodium chloride (NaCl): As chlorine gas displaces bromine, sodium chloride will be formed.
- Bromine (Br₂): Since chlorine gas is reacting with sodium bromide, some of the bromine will be released as free bromine (diatomic molecule - Br₂).

Based on the reaction equation and the prediction of products, the correct answers to the given questions are:
- The type of reaction is A) Single Replacement.
- The predicted product(s) are D) NaCl (Sodium chloride) and E) Br₂ (Bromine).