Iron has density 7.87 g/cm3. If 52.3 g of iron is added to 74.5 mL of water in a graduated cylinder, to what volume reading will the water level in the cylinder rise?
mL
Figured that one out. Thank you
To determine the volume reading to which the water level in the cylinder will rise, we need to subtract the volume occupied by the 52.3 g of iron from the initial volume of the water.
First, let's calculate the volume occupied by the iron:
Density of iron = 7.87 g/cm^3
Mass of iron = 52.3 g
Volume of iron = Mass of iron / Density of iron
Volume of iron = 52.3 g / 7.87 g/cm^3
Now, let's convert the volume of iron into milliliters:
1 cm^3 = 1 mL
Volume of iron = (52.3 g / 7.87 g/cm^3) * (1 cm^3 / 1 mL)
Volume of iron = 6.64 mL
Next, we subtract the volume of iron from the initial volume of water:
Initial volume of water = 74.5 mL
Volume reading to which the water level will rise = Initial volume of water - Volume of iron
Volume reading = 74.5 mL - 6.64 mL
Finally, we calculate the volume reading:
Volume reading = 67.86 mL
Therefore, the water level will rise to a volume reading of 67.86 mL in the graduated cylinder.
To find the volume reading to which the water level in the cylinder will rise, we need to calculate the volume of the added iron and then add it to the initial volume of water.
First, let's calculate the volume of the iron. We know the density of iron is 7.87 g/cm³ and we have 52.3 g of iron. We can use the formula:
Volume = Mass / Density
Volume = 52.3 g / 7.87 g/cm³ = 6.64 cm³
Now, we know that the initial volume of water in the graduated cylinder is 74.5 mL. To find the final volume, we add the volume of the iron to the initial volume of water:
Final Volume = Initial Volume of Water + Volume of Iron
Final Volume = 74.5 mL + 6.64 cm³
At this point, we need to ensure that the units are consistent. Since both volumes are given in different units (mL and cm³), we need to convert one of them. 1 mL is equivalent to 1 cm³, so we can simply add the two volumes together:
Final Volume = 74.5 mL + 6.64 cm³ = 81.14 mL
Therefore, the water level in the graduated cylinder will rise to a volume reading of 81.14 mL.
Volume = mass/density
volume Fe = 52.3/7.87 = ?
New volume water is the sum of initial volume + volume Fe.
Note that two objects can't occupy the same volume at the same time; therefore, the Fe must displace the water by the iron's volume.