if a color blind woman marries a man with normal vision,how do you set up punnett square?
let B meancolor blind gene, C means seeing color
Mom Dad
BB CC BC BC BC BC so all have one copy of colorblindness. So, if the children are girls, they will have normal vision, if males, they are colorblind (males only have one X, so if they Carry the B on their X, they are colorblind)
So the expected frquency is 1/2 kids will be colorblind (the boys), and one have color seeing (the girls).
To set up a Punnett square for a color blind woman (XcXc) marrying a man with normal vision (XCY), you will need to consider the inheritance pattern of color blindness, which is a recessive X-linked trait.
Step 1: Determine the genotype of each parent:
- The color blind woman's genotype is XcXc, meaning she carries two recessive color blindness alleles.
- The man with normal vision's genotype is XCY, meaning he carries one dominant normal vision allele and one recessive color blindness allele.
Step 2: Write the genotypes of the parents along the top and left side of the Punnett square:
Xc Xc
----------------
Xc |
----------------
YC |
Step 3: Combine the alleles from each parent to fill in the Punnett square. Remember, the woman only has one type of allele (Xc), and the man has two types of alleles (XC and YC).
Xc Xc
----------------
Xc | XcXc XcXc
----------------
YC | XCYc XCYc
Step 4: Analyze the results:
- The Punnett square shows that there are four possible combinations of alleles in their offspring.
- Two possibilities (XcXc) represent color blind daughters.
- One possibility (XCYc) represents a carrier daughter (normal vision but carries the color blindness allele).
- The remaining possibility (XCYc) represents a son with normal vision.
Please note that this Punnett square represents the possible genotypes of their offspring. The actual phenotypes (physical appearance) may vary as there could be other genes at play that influence eye color or other aspects of vision.
To set up a Punnett square for the color blindness trait, we need to understand the inheritance pattern of color blindness. Color blindness is a recessive trait that is carried on the X-chromosome.
In this scenario, let's assume that the woman is color blind (alleles XcXc) and the man has normal vision (alleles XNXN).
The Punnett square can be set up as follows:
| Xc | XN
---------------------
Xc | XcXc | XcXN
---------------------
XN | XcXN | XNXN
The columns represent the alleles inherited from the man, and the rows represent the alleles inherited from the woman.
Each box in the Punnett square represents a possible combination of alleles that their children may inherit.
Here's what each genotype represents:
- XcXc: Color blind female (affected)
- XcXN: Female carrier of color blindness (with normal vision)
- XNXN: Female with normal vision
In terms of phenotypes (the observable traits):
- Color blind females (XcXc) will exhibit color blindness.
- Female carriers (XcXN) may not have color blindness symptoms but can pass the trait to their children.
- Females with normal vision (XNXN) will not have or carry the color blindness trait.
It's important to note that if a male inherits the Xc allele from his mother, he will be color blind since he only has one X-chromosome.