An atom of gold has a mass of approximately 3.25 × 10−22 grams. What is the mass of 7000 atoms of gold? Express your answer in scientific notation

Online, “*” is used to indicate multiplication to avoid confusion with “x” as an unknown.

Online "^" is used to indicate an exponent, e.g., x^2 = x squared.

(3.25*10^-22)(7*10^3) = ?

Multiply the regular numbers and add the exponents.

To find the mass of 7000 atoms of gold, we can multiply the mass of one atom of gold by the number of atoms.

Mass of one atom of gold = 3.25 × 10^(-22) grams

Mass of 7000 atoms of gold = (3.25 × 10^(-22) grams) × (7000 atoms)

To multiply two numbers in scientific notation, we multiply the coefficients and add the exponents:

(3.25 × 10^(-22)) × (7000) = 22.75 × 10^(-22 + 3) = 22.75 × 10^(-19)

Therefore, the mass of 7000 atoms of gold is approximately 22.75 × 10^(-19) grams in scientific notation.

To find the mass of 7000 atoms of gold, we can multiply the mass of one atom by 7000.

The mass of one atom of gold is given as approximately 3.25 × 10^−22 grams.

To multiply this mass by 7000, we can use the following steps:

1. Multiply the numerical parts: 3.25 x 7000 = 22,750.
2. Add the exponents: -22 + 0 = -22.
3. Express the result in scientific notation: 2.275 × 10^4.

Therefore, the mass of 7000 atoms of gold is approximately 2.275 × 10^4 grams.

An atom of gold has a mass of 3.21x10^-22.What is the mass of 5000 atoms of gold.