the length of a rectangle L metres and the width of the rectangle is W metres. Each measurement is correct to the nearest cm. Find, in terms of L and W the difference between the lower bound and the upper bound of the area of the rectangle.

L 9 W 10 Total 21

What is Pi squared?

what's 9+10?

To find the difference between the lower bound and the upper bound of the area of the rectangle, we need to consider the possible range of values for both the length (L) and width (W) of the rectangle.

Since each measurement is correct to the nearest cm, we will assume that the actual length and width lie within a range of ±0.5 cm of the given measurements.

For the length (L), the lower bound would be L - 0.5 cm, and the upper bound would be L + 0.5 cm.

Similarly, for the width (W), the lower bound would be W - 0.5 cm, and the upper bound would be W + 0.5 cm.

The area (A) of a rectangle is given by the formula: A = L * W.

Now, we can find the lower and upper bounds for the area:

Lower bound of the area (A_lower) = (L - 0.5 cm) * (W - 0.5 cm)
Upper bound of the area (A_upper) = (L + 0.5 cm) * (W + 0.5 cm)

To find the difference between the lower and upper bounds of the area, we subtract the lower bound from the upper bound:

Difference = A_upper - A_lower

Substituting the values, we get:

Difference = [(L + 0.5 cm) * (W + 0.5 cm)] - [(L - 0.5 cm) * (W - 0.5 cm)]

Simplifying the equation further would involve expanding the brackets and combining like terms. However, since the original question only asks for the difference in terms of L and W, we'll leave it at this general form.