Find the coefficient of friction between a 73kg cubic box measuring 3m and a hardwood floor 16m long and 20m wide if a total of 236N is required to start the box moving.
546 n
To find the coefficient of friction between the box and the hardwood floor, we can use the formula:
Coefficient of friction (µ) = force of friction (Ff) / normal force (Fn)
First, let's calculate the force of friction. We know that a total of 236N is required to start the box moving. This force is known as the static friction. Once the box starts moving, we will use a different formula to find the dynamic friction. However, since the question only mentions the requirement to start the box moving, we will assume that is the only value provided.
Now, to calculate the force of friction, we need to multiply the normal force by the coefficient of friction. The normal force (Fn) is equal to the weight of the box (mg), where m is the mass of the box and g is the acceleration due to gravity (approximately 9.8 m/s^2).
The weight (mg) = mass (m) * acceleration due to gravity (g)
So, weight (mg) = 73 kg * 9.8 m/s^2 = 715.4 N
Therefore, the normal force (Fn) = 715.4 N
Now we can calculate the coefficient of friction (µ):
µ = Ff / Fn = 236 N / 715.4 N
Now we can do the calculation:
Coefficient of friction (µ) = 0.3293
Therefore, the coefficient of friction between the box and the hardwood floor is approximately 0.3293.