a second's pendulum is suspended from the roof of the lift.what will be the time period of the pendulum if the lift is moving up with an acceleration 20m/s^2
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To determine the time period of the pendulum in this scenario, we need to consider the effects of acceleration on the pendulum.
The time period of a simple pendulum is given by the formula:
T = 2π * √(L/g),
where T represents the time period, L represents the length of the pendulum, and g represents the acceleration due to gravity (approximately 9.8 m/s^2).
In this case, since the pendulum is suspended from the roof of the lift, the effective acceleration due to gravity will be reduced by the acceleration of the lift.
To find the effective acceleration due to gravity, we subtract the acceleration of the lift (20 m/s^2) from the acceleration due to gravity (9.8 m/s^2):
g_effective = g - a,
where a represents the acceleration of the lift.
Substituting this effective acceleration into the formula, we can find the time period:
T = 2π * √(L / g_effective).
Therefore, the time period of the pendulum when the lift is moving up with an acceleration of 20 m/s^2 can be calculated using this formula.