How much thermal energy is needed to raise the temperature of 4.0 kg of water from 25 degrees Celsius to 75 degrees Celsius?
To calculate the amount of thermal energy needed to raise the temperature of water, we can use the specific heat capacity of water, which is 4,186 J/kg°C.
The formula to calculate thermal energy is:
Q = m * c * ΔT
where:
Q is the thermal energy
m is the mass of the water
c is the specific heat capacity of water
ΔT is the change in temperature
In this case, the mass of water (m) is 4.0 kg, the specific heat capacity of water (c) is 4,186 J/kg°C, and the change in temperature (ΔT) is 75°C - 25°C = 50°C.
Plugging these values into the formula:
Q = 4.0 kg * 4,186 J/kg°C * 50°C
Calculating:
Q = 837,200 J
Therefore, the amount of thermal energy needed to raise the temperature of 4.0 kg of water from 25°C to 75°C is 837,200 Joules.
To determine the amount of thermal energy needed to raise the temperature of a substance, you can use the formula:
Q = mcΔT
Where:
Q is the thermal energy (in joules),
m is the mass of the substance (in kilograms),
c is the specific heat capacity of the substance (in joules per kilogram per degree Celsius), and
ΔT is the change in temperature (in degrees Celsius).
For water, the specific heat capacity is approximately 4,186 J/kg°C.
Given:
m = 4.0 kg (mass of water)
ΔT = (75°C - 25°C) = 50°C (change in temperature)
c (specific heat capacity of water) = 4,186 J/kg°C
We can substitute these values into the formula:
Q = (4.0 kg) x (4,186 J/kg°C) x (50°C)
Calculating this equation gives us:
Q = 837,200 J
Therefore, it takes 837,200 joules of thermal energy to raise the temperature of 4.0 kg of water from 25 degrees Celsius to 75 degrees Celsius.