Bob fires a cannon horizontally off a 125 meter cliff.the cannonball leaves the cannon traveling at 144 meters per second. How far from the cliff will the cannonball land?
h = 0.5*t^2 = 125 m.
4.9t^2 = 125
t^2 = 25.51
Tf = 5.05 s. = Fall time.
Dx = Xo * Tf = 144m/s * 5.05s = 727 m.
From the cliff.
To determine how far from the cliff the cannonball will land, we can use the laws of physics, specifically the motion equations for projectile motion.
In this case, since the cannonball is fired horizontally, the initial vertical velocity is zero. The only vertical force acting on the cannonball is gravity, which will cause it to accelerate downward at a rate of 9.8 m/s^2.
We can use the following equation to find the time it takes for the cannonball to reach the ground:
h = (1/2) * g * t^2
Where:
- h is the vertical distance (125 meters in this case)
- g is the acceleration due to gravity (9.8 m/s^2)
- t is the time taken
Simplifying the equation, we get:
t = sqrt(2h / g)
Plugging in the values:
t = sqrt(2 * 125 / 9.8) = 5.06 seconds (rounded to the nearest hundredth)
Now that we know the time it takes for the cannonball to reach the ground, we can calculate the horizontal distance it covers using the equation:
d = v * t
Where:
- d is the horizontal distance
- v is the horizontal velocity (which is the same as the initial horizontal velocity of the cannonball, since there is no horizontal force acting on it)
Plugging in the values:
d = 144 m/s * 5.06 s = 728.64 meters (rounded to the nearest hundredth)
Therefore, the cannonball will land approximately 728.64 meters from the cliff.