An apple falls from a tree and hits the ground 10.4 m below.
With what speed will it hit the ground? The acceleration of gravity is 9.8 m/s2
s = 1/2 at^2
v = at = √(2as)
So, just plug in the numbers to get v.
To find the speed at which the apple hits the ground, we can use the equations of motion. In this case, we can use the second equation of motion:
v² = u² + 2as
Where:
v is the final velocity (speed) of the apple
u is the initial velocity of the apple (which is 0 because the apple was dropped from rest)
a is the acceleration due to gravity (provided as 9.8 m/s²)
s is the displacement or distance fallen by the apple (provided as 10.4 m)
Plugging in the given values into the equation, we get:
v² = 0² + 2 * 9.8 * 10.4
Simplifying further:
v² = 2 * 9.8 * 10.4
v² = 203.84
Taking the square root of both sides gives us:
v ≈ √203.84
v ≈ 14.28 m/s
Therefore, the apple will hit the ground with a speed of approximately 14.28 m/s.