How many grams of ethanol(C2H60) are formed from .550 moles of sucrose(C12H22O11)?
To find the number of grams of ethanol formed from a given number of moles of sucrose, we need to use the balanced chemical equation for the reaction between sucrose and ethanol.
The balanced chemical equation for the reaction is:
C12H22O11 + H2O → 4C2H5OH
According to the equation, 1 mole of sucrose (C12H22O11) reacts to produce 4 moles of ethanol (C2H5OH).
First, calculate the number of moles of ethanol formed from 0.550 moles of sucrose:
0.550 moles C12H22O11 × (4 moles C2H5OH / 1 mole C12H22O11) = 2.2 moles C2H5OH
Now, to find the mass of ethanol formed, we can use the formula:
Mass (in grams) = Number of moles × Molar mass
The molar mass of ethanol (C2H5OH) can be calculated by adding the atomic masses of carbon (C), hydrogen (H), and oxygen (O) in the molecule:
Molar mass C2H5OH = (2 × atomic mass C) + (6 × atomic mass H) + atomic mass O
Using the atomic masses from the periodic table:
Molar mass C2H5OH = (2 × 12.01 g/mol) + (6 × 1.01 g/mol) + 16.00 g/mol
Molar mass C2H5OH ≈ 46.07 g/mol
Finally, substitute the values into the formula:
Mass (in grams) = 2.2 moles × 46.07 g/mol
Mass (in grams) ≈ 101.35 grams
Therefore, approximately 101.35 grams of ethanol (C2H5OH) are formed from 0.550 moles of sucrose (C12H22O11).
To calculate the number of grams of ethanol formed from a given number of moles of sucrose, we need to use the balanced chemical equation for the reaction.
The balanced equation for the combustion of sucrose (C12H22O11) to form ethanol (C2H6O) can be written as:
C12H22O11 -> 12C + 11H2O
12C + 22H + 11O -> C2H6O
From the balanced equation, we can see that 1 mole of sucrose (C12H22O11) produces 12 moles of carbon (C) and 11 moles of water (H2O).
So, first, we need to calculate the number of moles of carbon produced from 0.550 moles of sucrose:
Moles of carbon = 0.550 moles of sucrose × 12 moles of carbon / 1 mole of sucrose
Moles of carbon = 6.600 moles of carbon
Next, we need to calculate the moles of ethanol formed from the moles of carbon:
Moles of ethanol = 6.600 moles of carbon × 1 mole of ethanol / 12 moles of carbon
Moles of ethanol = 0.550 moles of ethanol
Finally, we can calculate the grams of ethanol formed from the moles of ethanol, using the molar mass of ethanol:
Molar mass of ethanol (C2H6O) = 2(12.01 g/mol) + 6(1.01 g/mol) + 16.00 g/mol
Molar mass of ethanol (C2H6O) = 46.08 g/mol
Grams of ethanol = 0.550 moles of ethanol × 46.08 g/mol
Grams of ethanol = 25.344 grams of ethanol
Therefore, 25.344 grams of ethanol are formed from 0.550 moles of sucrose.