what would the output of this code be?
int startDay = 6;
int day = 22;
switch(startDay)
{
case 5: day += 1;
case 6: day = day + 1;
case 0: ++day;
case 1: day++;
case 2: day += 1;
default: day = day + 1;
}
printf("day: %d\n", day);
the answer is 27, but i thought it would just do case 6, so day +1 so 23
Well, it seems like you tripped over the switch statement! Let me help you untangle this knot of confusion.
In this code, the variable startDay has a value of 6. So, it enters the switch statement and matches the case 6. Then, it adds 1 to the variable day, making it 23.
But here comes the tricky part: there are no break statements after each case! This means that once a case is matched, the code execution falls through to the next case. So, after executing case 6 and increasing day to 23, it continues to case 0.
In case 0, it increments day by 1, making it 24. Then it goes to case 1, increases it again to 25, and so on without any breaks.
Finally, it reaches the default case, and yet again, it increments day by 1. At this point, day becomes 27.
Therefore, the output of this code would be "day: 27". It's like a little adventure where the code trips and stumbles through each case, adding to the day along the way.
In this code, the switch statement evaluates the value of the variable "startDay." Based on the value, it executes the corresponding case.
In this case, the value of "startDay" is 6, so it matches the case 6. However, one thing to note in switch statements is that if there is no "break" statement after a case, the execution will continue to the next case without evaluating its condition.
Let's go through the code step by step to see how the value of "day" changes:
1. The initial value of "day" is 22.
2. The switch statement evaluates the value of "startDay" as 6, and it matches the case 6.
3. Since there is no "break" statement, the execution continues to the next case, case 0.
4. The value of "day" is increased by 1 (now 23).
5. Again, there is no "break" statement, so the execution continues to the next case, case 1.
6. The value of "day" is increased by 1 again (now 24).
7. Again, there is no "break" statement, so the execution continues to the next case, case 2.
8. The value of "day" is increased by 1 once more (now 25).
9. Still, no "break" statement, so the execution moves to the default case.
10. The value of "day" is increased by 1 (now 26).
11. The switch statement is finished, and the code reaches the printf statement.
12. The output will be "day: 26" because the final value of "day" is 26.
Therefore, the expected output should be 26, not 27.
To determine the output of the given code, let's understand how the switch statement works in C.
In the provided code, the switch statement is used to evaluate the value of the variable "startDay." The value of "startDay" is 6 in this case.
When a matching case is found in the switch statement, the code will begin executing from that point. If there is no matching case, the code will execute the default case (if it exists).
Now, let's break down the code step by step:
1. The value of "startDay" is 6, so the case 6 is matched.
2. When the case 6 is matched, the code will start executing from that point. It increases the value of "day" by 1, making it 23.
However, there is no `break` statement in this switch statement, which means the execution will continue to the next case.
3. When the next case (case 0) is encountered, the value of "day" is incremented by 1 again, resulting in "day" being 24.
4. The next case (case 1) increments the value of "day" by 1, further increasing it to 25.
5. The subsequent case (case 2) adds 1 to "day," making it 26.
6. Finally, the default case is executed, and "day" is increased by 1 once again, resulting in "day" being 27.
Hence, the output of this code will be:
day: 27