The sun's energy melts part of a glacier of ice at 0 degrees Celsius. The sun supplies 880 kilocalories to a big glacier of ice at 0 degrees Celsius. How many kilograms of ice will melt into liquid water at 0 degrees Celsius?

See your other post. Same process.

To find the number of kilograms of ice that will melt into liquid water, we need to determine the amount of heat required to melt a given quantity of ice. This can be done by using the concept of specific heat capacity.

The equation we will use is:

Q = mc∆T

Where:
Q is the heat energy supplied to the ice (in calories or kilocalories),
m is the mass of the ice (in grams or kilograms),
c is the specific heat capacity of ice (in calories/gram°C or kilocalories/kilogram°C),
∆T is the change in temperature.

In this case, the sun supplies 880 kilocalories of energy to the ice at 0 degrees Celsius. The specific heat capacity of ice is approximately 0.5 kilocalories/kilogram°C.

Substituting these values into the equation:

880 kilocalories = m * 0.5 kilocalories/kilogram°C * (0 - 0) degrees Celsius

Simplifying the equation, we can see that the change in temperature (∆T) is zero since the ice remains at 0 degrees Celsius.

This leaves us with the equation:

880 kilocalories = m * 0.5 kilocalories/kilogram°C * 0

Since multiplying any number by zero yields zero, we can conclude that the mass of the ice (m) is also zero. Therefore, no kilograms of ice will melt into liquid water with the given conditions.

However, it's important to consider that this answer assumes perfect efficiency in the energy transfer from the sun to the ice. In reality, there may be inefficiencies and factors such as the environment or other conditions that could affect the melting process.