a cyclist accelerates from rest to 8 m/s in 3 seconds. what in his acceleration? is this acceleration higher than that of a car which accelarates from 0 to 40 m/s in 8 seconds?
WO
(8m/s)/(3s) = 8/3 m/s^2
(40m/s)/(8s) = 5 m/s^2
which is greater?
To find the acceleration of the cyclist, we can use the equation:
acceleration = (final velocity - initial velocity) / time
Given that the cyclist starts from rest (initial velocity = 0 m/s) and reaches a final velocity of 8 m/s in 3 seconds,
acceleration = (8 m/s - 0 m/s) / 3 s = 8 m/s / 3 s ≈ 2.67 m/s²
So, the acceleration of the cyclist is approximately 2.67 m/s².
To compare this acceleration with that of a car, let's find the acceleration of the car:
acceleration = (final velocity - initial velocity) / time
Given that the car starts from rest (initial velocity = 0 m/s) and reaches a final velocity of 40 m/s in 8 seconds,
acceleration = (40 m/s - 0 m/s) / 8 s = 40 m/s / 8 s = 5 m/s²
Therefore, the acceleration of the car is 5 m/s².
Since 5 m/s² is greater than 2.67 m/s², the acceleration of the car is higher than that of the cyclist.