If 8.16 g of CuNO3 is dissolved in water to make a 0.500 M solution, what is the volume of the solution?
I wonder if you really meant CuNO3. I'll assume you did.
mols CuNO3 = grams/molar mass = ?
The M = mols/L solution. You know M and you know mols, solve for L solution.
To find the volume of the solution, we need to use the formula for molarity:
Molarity (M) = moles of solute / volume of solution (in liters)
In this case, we are given the molarity (0.500 M) and the mass of the solute (8.16 g of CuNO3). However, before we can use the formula, we need to convert the mass of CuNO3 to moles.
To convert grams to moles, we use the molar mass of CuNO3, which is the sum of the atomic masses of copper (Cu), nitrogen (N), and oxygen (O).
The atomic mass of Cu is 63.55 g/mol, the atomic mass of N is 14.01 g/mol, and the atomic mass of O is 16.00 g/mol.
Adding them up, we get:
63.55 + 14.01 + (16.00 * 3) = 63.55 + 14.01 + 48.00 = 125.56 g/mol.
Now, we can calculate the number of moles of CuNO3:
moles = mass / molar mass
moles = 8.16 g / 125.56 g/mol
moles ≈ 0.065 moles.
We now have the moles of solute (CuNO3) and the molarity (0.500 M), so we can rearrange the formula to find the volume:
Volume = moles / Molarity
Volume = 0.065 moles / 0.500 M
Volume ≈ 0.13 L.
Therefore, the volume of the solution is approximately 0.13 liters.