Solving By Factoring
2x(2x+1)=2
Please show work!!!
follow the same steps I showed you yesterday for the same type of problem
http://www.jiskha.com/display.cgi?id=1415491412
expand first, then bring everybody to the left and factor.
Remember the right side has to be zero.
Thank you
that's for another problem show me how to do this one
To solve the equation 2x(2x + 1) = 2 by factoring, we need to find the factors of 2 that will give us a product of 2.
Step 1: Distribute the 2x to both terms inside the parentheses.
2x * 2x + 2x * 1 = 2
This simplifies to:
4x^2 + 2x = 2
Step 2: Move all terms to one side of the equation to set it equal to zero.
4x^2 + 2x - 2 = 0
Step 3: To factor the quadratic equation, we need to find two numbers that multiply to give -8 and add up to 2. These numbers are -2 and 1.
4x^2 + 2x - 2 = (4x^2 - 2x) + (2x - 2)
= 2x(2x - 1) + 2(x - 1)
= 2x(2x - 1) + 2(x - 1)
Step 4: Now that we have factored the equation, we can set each factor equal to zero and solve for x.
Setting 2x = 0:
2x = 0
x = 0
Setting (2x - 1) = 0:
2x - 1 = 0
2x = 1
x = 1/2
Therefore, the solution to the equation 2x(2x + 1) = 2 is x = 0 and x = 1/2.