Calculate the escape velocity on the surface ov moon .Given the radius of moon=1.7×10(raise to power 6)m and mass of moon =7.35×10(raise to power 22)kg

2.4 km/s

To calculate the escape velocity on the surface of the moon, we can use the formula:

Escape Velocity (V) = √(2 * G * M / R)

Where:
- G is the gravitational constant (approximately equal to 6.674 × 10^-11 m^3/(kg * s^2)),
- M is the mass of the moon, and
- R is the radius of the moon.

Given the values:
- Mass of the moon (M) = 7.35 × 10^22 kg
- Radius of the moon (R) = 1.7 × 10^6 m

Now we can substitute the values into the formula:

V = √(2 * G * M / R)
V = √(2 * 6.674 × 10^-11 m^3/(kg * s^2) * 7.35 × 10^22 kg / 1.7 × 10^6 m)

Let's calculate this using a calculator:

V ≈ √(1.73316 × 10^12 m^3/(kg * s^2) * 4.323529 × 10^16 kg / 1.7 × 10^6 m)
V ≈ √11.10218 × 10^28 m^4/(kg^2 * s^2) / 1.7 × 10^6 m
V ≈ √6.530104 × 10^22 m^3/(kg * s^2)
V ≈ 8,011.84 m/s

Therefore, the escape velocity on the surface of the moon is approximately 8,011.84 m/s.