How many joules of heat need to be removed to condense 1.50 kg of steam at 100°C
-Specific Heat for steam is 2000 J/kg°C-
q = mass H2O x delta Hvap.
You don't need the specific heat H2O. You need the delta H vaporization/condensation.
Thank you for clearing that up
(1.50*2.26*10^6)= 3.39*10^6 J
I agree
To find the amount of heat that needs to be removed to condense the steam, we need to use the formula:
Q = m * ΔH
where:
Q is the amount of heat (in joules)
m is the mass of the substance (in kg)
ΔH is the specific heat (in J/kg°C)
In this case, we want to condense 1.50 kg of steam at 100°C. We are given the specific heat for steam as 2000 J/kg°C.
So, plugging these values into the formula, we have:
Q = 1.50 kg * 2000 J/kg°C * (100°C - 0°C)
Q = 1.50 kg * 2000 J/kg°C * 100°C
Q = 300,000 J
Therefore, 300,000 Joules of heat need to be removed to condense 1.50 kg of steam at 100°C.