How many joules of heat need to be removed to condense 1.50 kg of steam at 100°C

-Specific Heat for steam is 2000 J/kg°C-

To calculate the amount of heat that needs to be removed to condense 1.50 kg of steam at 100°C, we can use the formula:

Q = m * ΔH

where:
Q is the amount of heat (in joules),
m is the mass of the substance (in kg), and
ΔH is the enthalpy change (in J/kg).

In this case, the mass (m) is given as 1.50 kg, and the specific heat for steam is given as 2000 J/kg°C. However, the specific heat is not relevant for calculating the heat of condensation.

The heat of condensation (ΔH) for steam at 100°C is approximately 2260 J/g. However, the given mass is in kilograms. Since there are 1000 grams in a kilogram, we need to convert ΔH to J/kg.

To convert ΔH to J/kg:
(2260 J/g) * (1000 g/kg) = 2260000 J/kg

Now we can substitute the values into the formula:

Q = m * ΔH
Q = 1.50 kg * 2260000 J/kg

Calculating this, we get:
Q = 3390000 J

Therefore, approximately 3,390,000 joules of heat need to be removed to condense 1.50 kg of steam at 100°C.