A 244 g particle is released from rest at point A inside a smooth hemispherical bowl of ra- dius 21.7 cm, as shown in the figure
The acceleration of gravity if 9.81 m/s2 .
To determine the acceleration of the particle inside the bowl, we need to consider the forces acting on the particle.
Initially, when the particle is at point A and is released from rest, the only force acting on it is the force of gravity, which is directed vertically downwards. The magnitude of this force can be calculated using the formula F = m * g, where F is the force, m is the mass of the particle, and g is the acceleration due to gravity.
Given that the mass of the particle is 244 g (which is equal to 0.244 kg) and the acceleration due to gravity is 9.81 m/s^2, we can calculate the force of gravity as follows:
F = m * g
F = 0.244 kg * 9.81 m/s^2
F = 2.39 N
At any point inside the bowl, the force of gravity is acting vertically downwards. However, the surface of the bowl exerts a normal force perpendicular to the surface, which opposes the force of gravity. In a smooth bowl, the normal force is equal in magnitude and opposite in direction to the force of gravity. Therefore, the net force acting on the particle is zero, and consequently, the acceleration of the particle is also zero.
In summary, the acceleration of the particle inside the smooth hemispherical bowl is zero.