which number is a perfect cube

a.7
b. 25
c. 66<----
d. 27

I just did the test here are the answers :D

3. 1.3 (D)
4. 10 ft (B)
5. 27 (D)
6. Integer (A)
7. 6/7 (C)
8. 4ft (B)
9. 5.3 (B)
10. Riley (C)
11. 0.123123...(C)
12. 13ft (B)
13. 29 (B)
14. Every rational number can be written as a fraction (C)
1,2,15,16,17,18, On your own

The questions changed this year 😔😔

c is wrong

3^3 = 27 , so 27 is a perfect cube.

27

the dude who wrote this is probably in college right now or he gots a job lol

ok thanks

I'm not a math teacher, but I don't think so!! What is x^3 that results in 66?

omg when you take the test can you pls gimme the answers after words

I got y'all

2) Just look up what the definition of the word is and explain how it is a perfect square.
3) 1.3 (D)
4) 17 meters (C)
5) 27 (D)
6) Integer (A)
7) 6/7 (C)
8) 5 feet (B)
9) 10 in. (A)
10) Carley (B)
11) 123123123... (C)
12) 13ft. (B)
13) 21ft. (B)
14) Every rational number can be written as a fraction (C)
15) V = s^3
216 = s^3
6^3 = 216
216 = 216
s^3 = 6in.
The length of each side of the box is 6 inches.
16) Just look up the question and it would be on brainly.
17) Just find out which one of the figures is equal to the bigger side. The numbers are already squared so just add the two smallest squares together and see which one equals the biggest square and if it does it's the right Figure (Figure B). Then explain what you did to find the answer.

(Your Welcome Students)

To determine which number is a perfect cube, we need to understand what a perfect cube means. A perfect cube is a number that can be expressed as the cube of an integer, or in other words, a number multiplied by itself twice.

Now, let's check the given options:

a. 7: To check if 7 is a perfect cube, we need to find an integer whose cube is 7. In this case, there is no integer that, when multiplied by itself twice, would result in 7. Therefore, 7 is not a perfect cube.

b. 25: Similarly, we need to find an integer whose cube is 25. By trying different integers, we find that 2³ = 8, 3³ = 27, and 4³ = 64. Since there is no integer whose cube is 25, we can conclude that 25 is not a perfect cube.

c. 66: Again, we need to find an integer whose cube is 66. By trying different integers, we find that 4³ = 64 and 5³ = 125. Since there is no integer whose cube is 66, we can conclude that 66 is not a perfect cube.

d. 27: Finally, we need to find an integer whose cube is 27. By trying different integers, we find that 3³ = 27. Therefore, 27 is a perfect cube.

So, out of the given options, the number 27 is a perfect cube.