Two poles 13m and 18m high stand upright on a playground if their feet are 12m apart find the distance between their tops
make your sketch
draw a horizontal line from the top of the shorter pole to the other pole.
You now have a right-angled triangle with base 12 m, height 18-13 or 5 m
You should recognize the common 5,12, 13 right-angled triangle, if not
c^2 = 12^2 + 5^2 = 169
c =√169 = 13
13m
I don't know
It's a tough question
2+2÷2=3
Why use ^ this sing I don't understand this so another method can I will share to give me answer
H square = p square + b square
To find the distance between the tops of the two poles, we can use the Pythagorean theorem. According to the theorem, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, we can consider one of the poles as the hypotenuse, so we have a right triangle with one side being the height of the shorter pole (13m), another side being the height of the taller pole (18m), and the remaining side being the distance between their feet (12m).
Let's denote the distance between the tops of the poles as 'd'. Using the Pythagorean theorem, we have:
d² = (18m)² - (13m)²
Simplifying this equation, we get:
d² = 324m² - 169m²
d² = 155m²
Finally, taking the square root of both sides, we find:
d = √155m or approximately 12.45m
Therefore, the distance between the tops of the two poles is approximately 12.45 meters.