The sum of two numbers s 96, and their difference is 17. What is the larger of these two numbers ?
let x be the larger
then the smaller is 96-x
x - (96-x) = 17
x - 96 + x = 17
2x = 113
x = 56.5
larger is 56.5 , the smaller is 39.5
check:
difference = 56.5-39.5 = 17 , yup!!
The difference two numbers is -11. Their sum is -17. Find the numbers
To solve this problem, we can set up a system of equations based on the given information.
Let's assume that the two numbers are x and y.
According to the problem, the sum of the two numbers is 96, so we can write the equation as:
x + y = 96
The difference between the two numbers is 17, so we can write another equation as:
x - y = 17
Now, we have a system of equations:
x + y = 96
x - y = 17
To find the larger of the two numbers, we need to solve this system of equations.
One way to do this is by using the method of elimination. We can add both equations together to eliminate y:
(x + y) + (x - y) = 96 + 17
Simplifying this equation gives us:
2x = 113
Now, we can solve for x by dividing both sides of the equation by 2:
x = 113 / 2
x = 56.5
Substituting the value of x back into one of the original equations, we can solve for y:
56.5 + y = 96
y = 96 - 56.5
y = 39.5
So the two numbers are approximately 56.5 and 39.5. The larger of these two numbers is 56.5.