Carl has 5/6 yard long, 1/4 yard long, and 2/3 yard long of cable wire. After Carl used 1 yard how much cable wire would he have?
5/6 = 10/12
1/4 = 3/12
2/3 = 8/12
21/12 = 12/12 = 9/12 = 3/4 yard
What is the answer to the questions because I'm confused about it forreal tell the answer
To find the answer, we need to add up the lengths of the three pieces of cable wire and subtract 1 yard after Carl used it.
First, let's add the lengths of the three pieces of cable wire together:
5/6 + 1/4 + 2/3
To add fractions with different denominators, we need to find a common denominator. In this case, the smallest number that all the denominators (6, 4, and 3) divide into evenly is 12.
Now, let's convert each fraction so that they have a denominator of 12:
5/6 = (5/6) * (2/2) = 10/12
1/4 = (1/4) * (3/3) = 3/12
2/3 = (2/3) * (4/4) = 8/12
Now that all the fractions have the same denominator, we can add them together:
10/12 + 3/12 + 8/12 = 21/12
Now, since 21/12 is an improper fraction (numerator is greater than the denominator), we can simplify it:
21/12 = 1 and 9/12 = 1 and 3/4
Therefore, Carl initially had a total of 1 and 3/4 yards of cable wire.
Next, Carl used 1 yard of cable wire. To find how much cable wire he would have left, we need to subtract the length he used from his initial amount:
1 and 3/4 - 1 = 3/4
Therefore, after Carl used 1 yard of cable wire, he would have 3/4 yard of cable wire left.
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It is....
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