Seth had a bag with 4 green, 5 yellow, and 6 blue marbles in it. If Seth draws a yellow marble and does not replace it, what is the probability that the second marble he draws is yellow?
2/7
its wrong lol
To find the probability that Seth draws a yellow marble for the second time, we need to consider the number of yellow marbles left in the bag and the total number of marbles left.
First, when Seth draws a yellow marble from the bag, there are now 4 green, 4 yellow, and 6 blue marbles left.
The total number of marbles left in the bag after the first draw is 4 + 4 + 6 = 14.
Since Seth does not replace the first yellow marble, there will be one less marble in the bag for the second draw.
So, the probability of drawing a yellow marble for the second time is calculated as follows:
Number of yellow marbles left in the bag after the first draw / Total number of marbles left in the bag after the first draw
The number of yellow marbles left in the bag after the first draw is 4.
The total number of marbles left in the bag after the first draw is 14 - 1 = 13.
Thus, the probability that Seth draws a yellow marble for the second time is 4/13.