Consider the function y = –2(x – 12)^2 + 18.

a) What is the axis of symmetry of the graph of the function.(1 mark)

for any parabola of the form

y = a(x-h)^2 + k ,
the vertex is (h,k) and the axis of symmetry is x = h

so in your case ......

To find the axis of symmetry of a quadratic function in the form y = ax^2 + bx + c, you can use the formula x = -b/2a. This formula gives you the x-coordinate of the vertex of the quadratic function, and the axis of symmetry is a vertical line that passes through this point.

In the given function, y = –2(x – 12)^2 + 18, we can see that a = -2 and b = 12.

Using the formula x = -b/2a, we substitute the values of a and b:

x = -(12) / (2 * (-2))
x = -12 / (-4)
x = 3

The x-coordinate of the vertex is 3, which means the axis of symmetry is the vertical line x = 3.

Therefore, the axis of symmetry of the graph of the function y = –2(x – 12)^2 + 18 is x = 3.