Cs(s)+H2O(l)→ ?
i thought it was H2+CsOH but the computer says that's wrong.
You have to balance the equation
The answer that you provided is in fact incorrect. The H2+CsOH on the right side of the equation contains 3 hydrogen atoms. However, you only have 2 hydrogen atoms on the left side of the equation. Therefore, your equation is unbalanced. Keep trying!
The correct balanced equation for the reaction between solid cesium (Cs) and liquid water (H2O) is:
2Cs(s) + 2H2O(l) → 2CsOH(aq) + H2(g)
This equation shows that two moles of solid cesium react with two moles of liquid water to produce two moles of aqueous cesium hydroxide (CsOH) and one mole of hydrogen gas (H2).
To determine the correct chemical equation for the reaction between Cs(s) (cesium) and H2O(l) (water), we need to consider their respective reactivity.
Cesium is a highly reactive metal from Group 1 of the periodic table, known as alkali metals. It reacts vigorously with water to form an alkali metal hydroxide and hydrogen gas.
The balanced chemical equation for the reaction between Cs(s) and H2O(l) can be written as:
2Cs(s) + 2H2O(l) → 2CsOH(aq) + H2(g)
In this equation, two cesium atoms (Cs) react with two water molecules (H2O) to produce two cesium hydroxide molecules (CsOH) in the aqueous state and one molecule of hydrogen gas (H2) in the gaseous state.
It seems like you made a slight error in the coefficients. The balanced equation requires two Cs atoms reacting with two H2O molecules. Therefore, the correct reaction products are CsOH(aq) and H2(g).
Please note that aqueous (aq) represents a substance dissolved in water, and (g) denotes a gas.