Waiting times at a doctor office are normally distributed with a mean of 35 minutes, and a standard deviation of 10 minutes. What is the chance a patient would have to wait over 50 minutes?
Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
To calculate the probability that a patient would have to wait over 50 minutes, we can use the concept of the standard normal distribution.
First, we standardize the value of 50 minutes by subtracting the mean (35 minutes) from it and dividing by the standard deviation (10 minutes):
z = (50 - 35) / 10
z = 15 / 10
z = 1.5
Now, we can use a standard normal distribution table or a statistical calculator to find the probability corresponding to a z-score of 1.5.
Using a standard normal distribution table, we can find the probability associated with a z-score of 1.5, which is approximately 0.9332.
Therefore, the probability that a patient would have to wait over 50 minutes is approximately 0.9332 or 93.32%.