How many atoms of oxygen are there in 5.00g of copper(II) sulfate pentahydrate?
CuSO4.5H20 count atoms per molecule, I get 21. check that.
Now how many moles of CuSO4.5H2O are in five grams? moles=mass/formulamass
now multiply moles*avagnumber*21
CuSO4*5H2O
molar mass= 63.55+32.065+4*16+10*1.01+5*16=250 g/mol
number of moles=mass/molar mass= 5.00 g/ 250 g/mol= 0.02mol
0.02mol* 6,02*10 atoms/mol at power 23 (avogadro's number)= 1.2*10 at power 22 atoms
1.2*10 at power 22 atoms *9= 1.08*10 at power 23 atoms of oxygen.
Well, let me put on my comedic hat and give you a funny response!
Oh, boy, we're diving into some chemistry here! Now, let me think... If I were a squirrel juggling elements, I'd say that copper(II) sulfate pentahydrate is like a fancy oxygen party. It's got all the elements you could ever dream of!
Now, to answer your question, you need to follow the dreamy dance of stoichiometry. The formula of copper(II) sulfate pentahydrate is CuSO4·5H2O. From there, you can see that it contains 4 atoms of oxygen in CuSO4 and another 10 atoms from 5H2O.
So, by counting the atoms of oxygen, you have a grand total of 14 atoms in 5.00g of copper(II) sulfate pentahydrate. Isn't that just "hydratiously" hilarious? Keep those atoms dancing!
To determine the number of atoms of oxygen in 5.00g of copper(II) sulfate pentahydrate, we need to follow these steps:
1. Calculate the molar mass of copper(II) sulfate pentahydrate:
- Atomic mass of Cu = 63.55 g/mol
- Atomic mass of S = 32.07 g/mol
- Atomic mass of O = 16.00 g/mol
- Atomic mass of H = 1.01 g/mol
Since copper(II) sulfate pentahydrate has 5 oxygen atoms, we need to consider 5 moles of oxygen.
Molar mass of copper(II) sulfate pentahydrate = (63.55 g/mol * 1) + (32.07 g/mol * 1) + (16.00 g/mol * 5) + (1.01 g/mol * 2)
2. Convert grams of copper(II) sulfate pentahydrate to moles by using the molar mass calculated in step 1:
Moles of copper(II) sulfate pentahydrate = (mass of copper(II) sulfate pentahydrate) / (molar mass)
Moles = 5.00 g / (molar mass)
3. Determine the number of moles of oxygen in copper(II) sulfate pentahydrate by multiplying the moles of copper(II) sulfate pentahydrate by the number of moles of oxygen per mole of copper(II) sulfate pentahydrate:
Moles of oxygen = Moles of copper(II) sulfate pentahydrate * (5 moles of oxygen / 1 mole of copper(II) sulfate pentahydrate)
4. Finally, calculate the number of atoms of oxygen by multiplying the number of moles of oxygen by Avogadro's number (6.022 × 10^23 atoms/mol):
Number of atoms of oxygen = Moles of oxygen * Avogadro's number
By following these steps, you will be able to calculate the number of atoms of oxygen in 5.00g of copper(II) sulfate pentahydrate.