Explain why (2,-3) would be the vertex of the function y=-3(x-2)^2-3? Please and thank you!
(x-2)^2 can never be negative. It is its minimum value of 0 when x=2.
So, the vertex is at x=2. y(2) = -3, so the vertex is at (2,-3)
So, the vertex is at x=2. y(2) = -3, so the vertex is at (2,-3)