Given f(2)=5, f'(2)=-1 find the value of d/dx[1/sqrt(f(2x))] when x=1
if g(x) = 1/√f(2x)
dg/dx = (-1/2)f(2x)^-3/2 * f'(2x) * 2
so,
g'(1) = (-1/2)f(2)^-3/2 * f'(2) * 2
= (-1/2)(5^-3/2)(-1)(2)
= 1 / 5√5
dg/dx = (-1/2)f(2x)^-3/2 * f'(2x) * 2
so,
g'(1) = (-1/2)f(2)^-3/2 * f'(2) * 2
= (-1/2)(5^-3/2)(-1)(2)
= 1 / 5√5