A roulette player makes a $10 wager that the ball will land on a specific number (this is known asa straight bet). The probability that the player wins this bet is 1/38 (and so the probability that he loses
What is your question?
Yes, the player is very likely to lose the $10.
To calculate the probability of winning a straight bet in roulette, we need to consider the total number of possible outcomes.
In roulette, there are 38 numbers on the wheel (0 to 36, plus an additional 00 in American roulette). Out of these 38 numbers, only one number represents a win for the player.
Therefore, the probability of winning the straight bet is 1 out of 38.
To verify this calculation, you can count the number of favorable outcomes (in this case, winning numbers) and divide it by the total number of possible outcomes (38).
So, in this scenario, the probability of winning the straight bet is 1/38.
Since the question mentions the probability of losing, we can calculate it by subtracting the probability of winning from 1.
The probability of losing the straight bet would be: 1 - 1/38 = 37/38.
Thus, the probability that the player loses the bet is 37/38.